X^2+6x-134=0

Solution for X^2+6x-134=0 equation:

X^2+6X-134=0

a = 1; b = 6; c = -134;
Δ = b2-4ac
Δ = 62-4·1·(-134)
Δ = 572
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{572}=\sqrt{4*143}=\sqrt{4}*\sqrt{143}=2\sqrt{143}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{143}}{2*1}=\frac{-6-2\sqrt{143}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{143}}{2*1}=\frac{-6+2\sqrt{143}}{2}
$